Simplifying resistor networks
8:06
Khan AcademyWilly McAllister
Simplifying resistor networks
Learn strategies for combining resistors in series and parallel to simplify resistor networks.
9 months ago
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One way to calculate an equivalent resistance of a network is to apply a known voltage across it and measure the current drawn by the network. The equivalent resistance of this resistor tree is 4 Ω as it draws 1 A of current from a 4 V source. Let's confirm this. N resistors of N Ω connected in parallel are equivalent to 1 Ω. So each level of the tree behaves as a 1 Ω resistor. Four 1 Ω resistors in series is equivalent to 4 Ω. With EveryCircuit you can probably understand Kirchhoff's and Ohm's
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One way to calculate an equivalent resistance of a network is to apply a known voltage across it and measure the current drawn by the network. The equivalent resistance of this resistor tree is 4 Ω as it draws 1 A of current from a 4 V source. Let's confirm this. N resistors of N Ω connected in parallel are equivalent to 1 Ω. So each level of the tree behaves as a 1 Ω resistor. Four 1 Ω resistors in series is equivalent to 4 Ω. With EveryCircuit you can probably understand Kirchhoff's and Ohm's
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One way to calculate an equivalent resistance of a network is to apply a known voltage across it and measure the current drawn by the network. The equivalent resistance of this resistor tree is 4 Ω as it draws 1 A of current from a 4 V source. Let's confirm this. N resistors of N Ω connected in parallel are equivalent to 1 Ω. So each level of the tree behaves as a 1 Ω resistor. Four 1 Ω resistors in series is equivalent to 4 Ω. With EveryCircuit you can probably understand Kirchhoff's and Ohm's
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